Optimal. Leaf size=209 \[ -\frac{e^2 (-5 a B e-A b e+6 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 b^{7/2} (b d-a e)^{3/2}}-\frac{e \sqrt{d+e x} (-5 a B e-A b e+6 b B d)}{8 b^3 (a+b x) (b d-a e)}-\frac{(d+e x)^{3/2} (-5 a B e-A b e+6 b B d)}{12 b^2 (a+b x)^2 (b d-a e)}-\frac{(d+e x)^{5/2} (A b-a B)}{3 b (a+b x)^3 (b d-a e)} \]
[Out]
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Rubi [A] time = 0.403552, antiderivative size = 209, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.152 \[ -\frac{e^2 (-5 a B e-A b e+6 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 b^{7/2} (b d-a e)^{3/2}}-\frac{e \sqrt{d+e x} (-5 a B e-A b e+6 b B d)}{8 b^3 (a+b x) (b d-a e)}-\frac{(d+e x)^{3/2} (-5 a B e-A b e+6 b B d)}{12 b^2 (a+b x)^2 (b d-a e)}-\frac{(d+e x)^{5/2} (A b-a B)}{3 b (a+b x)^3 (b d-a e)} \]
Antiderivative was successfully verified.
[In] Int[((A + B*x)*(d + e*x)^(3/2))/(a^2 + 2*a*b*x + b^2*x^2)^2,x]
[Out]
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Rubi in Sympy [A] time = 76.6327, size = 187, normalized size = 0.89 \[ \frac{\left (d + e x\right )^{\frac{5}{2}} \left (A b - B a\right )}{3 b \left (a + b x\right )^{3} \left (a e - b d\right )} - \frac{\left (d + e x\right )^{\frac{3}{2}} \left (A b e + 5 B a e - 6 B b d\right )}{12 b^{2} \left (a + b x\right )^{2} \left (a e - b d\right )} - \frac{e \sqrt{d + e x} \left (A b e + 5 B a e - 6 B b d\right )}{8 b^{3} \left (a + b x\right ) \left (a e - b d\right )} + \frac{e^{2} \left (A b e + 5 B a e - 6 B b d\right ) \operatorname{atan}{\left (\frac{\sqrt{b} \sqrt{d + e x}}{\sqrt{a e - b d}} \right )}}{8 b^{\frac{7}{2}} \left (a e - b d\right )^{\frac{3}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(e*x+d)**(3/2)/(b**2*x**2+2*a*b*x+a**2)**2,x)
[Out]
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Mathematica [A] time = 0.581778, size = 168, normalized size = 0.8 \[ \frac{e^2 (5 a B e+A b e-6 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{8 b^{7/2} (b d-a e)^{3/2}}+\frac{\sqrt{d+e x} \left (\frac{3 e (a+b x)^2 (-11 a B e+A b e+10 b B d)}{a e-b d}-2 (a+b x) (-13 a B e+7 A b e+6 b B d)-8 (A b-a B) (b d-a e)\right )}{24 b^3 (a+b x)^3} \]
Antiderivative was successfully verified.
[In] Integrate[((A + B*x)*(d + e*x)^(3/2))/(a^2 + 2*a*b*x + b^2*x^2)^2,x]
[Out]
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Maple [B] time = 0.028, size = 487, normalized size = 2.3 \[{\frac{{e}^{3}A}{8\, \left ( bex+ae \right ) ^{3} \left ( ae-bd \right ) } \left ( ex+d \right ) ^{{\frac{5}{2}}}}-{\frac{11\,a{e}^{3}B}{8\, \left ( bex+ae \right ) ^{3}b \left ( ae-bd \right ) } \left ( ex+d \right ) ^{{\frac{5}{2}}}}+{\frac{5\,{e}^{2}Bd}{4\, \left ( bex+ae \right ) ^{3} \left ( ae-bd \right ) } \left ( ex+d \right ) ^{{\frac{5}{2}}}}-{\frac{{e}^{3}A}{3\, \left ( bex+ae \right ) ^{3}b} \left ( ex+d \right ) ^{{\frac{3}{2}}}}-{\frac{5\,a{e}^{3}B}{3\, \left ( bex+ae \right ) ^{3}{b}^{2}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}+2\,{\frac{{e}^{2} \left ( ex+d \right ) ^{3/2}Bd}{ \left ( bex+ae \right ) ^{3}b}}-{\frac{{e}^{4}Aa}{8\, \left ( bex+ae \right ) ^{3}{b}^{2}}\sqrt{ex+d}}+{\frac{{e}^{3}Ad}{8\, \left ( bex+ae \right ) ^{3}b}\sqrt{ex+d}}-{\frac{5\,B{e}^{4}{a}^{2}}{8\, \left ( bex+ae \right ) ^{3}{b}^{3}}\sqrt{ex+d}}+{\frac{11\,{e}^{3}Bda}{8\, \left ( bex+ae \right ) ^{3}{b}^{2}}\sqrt{ex+d}}-{\frac{3\,{e}^{2}B{d}^{2}}{4\, \left ( bex+ae \right ) ^{3}b}\sqrt{ex+d}}+{\frac{{e}^{3}A}{8\, \left ( ae-bd \right ){b}^{2}}\arctan \left ({b\sqrt{ex+d}{\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}} \right ){\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}}+{\frac{5\,a{e}^{3}B}{8\,{b}^{3} \left ( ae-bd \right ) }\arctan \left ({b\sqrt{ex+d}{\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}} \right ){\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}}-{\frac{3\,{e}^{2}Bd}{4\, \left ( ae-bd \right ){b}^{2}}\arctan \left ({b\sqrt{ex+d}{\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}} \right ){\frac{1}{\sqrt{b \left ( ae-bd \right ) }}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(e*x+d)^(3/2)/(b^2*x^2+2*a*b*x+a^2)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(e*x + d)^(3/2)/(b^2*x^2 + 2*a*b*x + a^2)^2,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.308962, size = 1, normalized size = 0. \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(e*x + d)^(3/2)/(b^2*x^2 + 2*a*b*x + a^2)^2,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(e*x+d)**(3/2)/(b**2*x**2+2*a*b*x+a**2)**2,x)
[Out]
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GIAC/XCAS [A] time = 0.294887, size = 514, normalized size = 2.46 \[ \frac{{\left (6 \, B b d e^{2} - 5 \, B a e^{3} - A b e^{3}\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{8 \,{\left (b^{4} d - a b^{3} e\right )} \sqrt{-b^{2} d + a b e}} - \frac{30 \,{\left (x e + d\right )}^{\frac{5}{2}} B b^{3} d e^{2} - 48 \,{\left (x e + d\right )}^{\frac{3}{2}} B b^{3} d^{2} e^{2} + 18 \, \sqrt{x e + d} B b^{3} d^{3} e^{2} - 33 \,{\left (x e + d\right )}^{\frac{5}{2}} B a b^{2} e^{3} + 3 \,{\left (x e + d\right )}^{\frac{5}{2}} A b^{3} e^{3} + 88 \,{\left (x e + d\right )}^{\frac{3}{2}} B a b^{2} d e^{3} + 8 \,{\left (x e + d\right )}^{\frac{3}{2}} A b^{3} d e^{3} - 51 \, \sqrt{x e + d} B a b^{2} d^{2} e^{3} - 3 \, \sqrt{x e + d} A b^{3} d^{2} e^{3} - 40 \,{\left (x e + d\right )}^{\frac{3}{2}} B a^{2} b e^{4} - 8 \,{\left (x e + d\right )}^{\frac{3}{2}} A a b^{2} e^{4} + 48 \, \sqrt{x e + d} B a^{2} b d e^{4} + 6 \, \sqrt{x e + d} A a b^{2} d e^{4} - 15 \, \sqrt{x e + d} B a^{3} e^{5} - 3 \, \sqrt{x e + d} A a^{2} b e^{5}}{24 \,{\left (b^{4} d - a b^{3} e\right )}{\left ({\left (x e + d\right )} b - b d + a e\right )}^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*(e*x + d)^(3/2)/(b^2*x^2 + 2*a*b*x + a^2)^2,x, algorithm="giac")
[Out]